(4/d-2)+(3d/d-2)=(8/d^2-4d+4)

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Solution for (4/d-2)+(3d/d-2)=(8/d^2-4d+4) equation: 



(4/d-2)+(3d/d-2)=(8/d^2-4d+4)

We move all terms to the left:

(4/d-2)+(3d/d-2)-((8/d^2-4d+4))=0



Domain of the equation: d-2)!=0

d∈R





Domain of the equation: d^2-4d+4))!=0

d∈R



We get rid of parentheses

4/d+3d/d-((8/d^2-4d+4))-2-2=0

We calculate fractions

We do not support edpression: d^3

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